ÌâÄ¿ÄÚÈÝ

ÓÒ±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö¡££¨¹²7·Ö£©

£¨1£©±íÖÐÔªËØ¢âµÄÇ⻯ÎïµÄ»¯Ñ§Ê½Îª           £¬´ËÇ⻯ÎïµÄ»¹Ô­ÐÔ±ÈÔªËØ¢áµÄÇ⻯ÎïµÄ»¹Ô­ÐÔ              £¨ÌîÇ¿»òÈõ£©

£¨2£©Ä³ÔªËØÔ­×ӵĺËÍâpµç×ÓÊý±Èsµç×ÓÊýÉÙ1£¬Ôò¸ÃÔªËصÄÔªËØ·ûºÅÊÇ      £¬Æäµ¥Öʵĵç×ÓʽΪ                 ¡£

£¨3£©ÒÑ֪ijЩ²»Í¬×åÔªËصÄÐÔÖÊÒ²ÓÐÒ»¶¨µÄÏàËÆÐÔ£¬ÈçÔªËØ¢ÛÓëÔªËØ¢àµÄÇâÑõ»¯ÎïÓÐÏàËƵÄÐÔÖÊ¡£Ð´³öÔªËØ¢ÛµÄÇâÑõ»¯ÎïÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ

                                                                 £¨2·Ö£©

ÓÖÈç±íÖÐÓëÔªËآߵÄÐÔÖÊÏàËƵIJ»Í¬×åÔªËØÊÇ            £¨ÌîÔªËØ·ûºÅ£©

 

¡¾´ð°¸¡¿

£¨1£©HCl¡¢Èõ

£¨2£©N  N2

£¨3£©Be(OH)2 + 2NaOH = Na2BeO2 + 2H2O£¬Li

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø