ÌâÄ¿ÄÚÈÝ

£¨8·Ö£©ÎªÁËÖ¤Ã÷ÔÚʵÑéÊÒÖƱ¸Cl2µÄ¹ý³ÌÖлáÓÐË®ÕôÆøºÍHCl»Ó·¢³öÀ´£¬¼×ͬѧÉè¼ÆÁËÈçÏÂͼËùʾµÄʵÑé×°Ö㬰´ÒªÇó»Ø´ðÎÊÌâ¡£

 

 

 

    ¢ÅÇë¸ù¾Ý¼×ͬѧµÄÒâͼ£¬Á¬½ÓÏàÓ¦µÄ×°Ö㬽ӿÚ˳Ðò£º

b½Ó________£¬__________½Ó _________£¬_________½Óa¡£

    ¢ÆUÐιÜÖÐËùÊ¢ÊÔ¼ÁµÄ»¯Ñ§Ê½Îª_____________________________ ¡£

    ¢Ç×°ÖâÛÖÐCCl4µÄ×÷ÓÃÊÇ___________________________________¡£

    ¢ÈÒÒͬѧÈÏΪ¼×ͬѧʵÑéÖÐÓÐȱÏÝ£¬²»ÄÜÖ¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ¡£ÎªÁËÈ·±£ÊµÑé½áÂ۵Ŀɿ¿ÐÔ£¬Ö¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ£¬ÒÒͬѧÌá³öÔÚijÁ½¸ö×°ÖÃÖ®¼äÔÙ¼Ó×°Öâݡ£ÄãÈÏΪװÖâÝÓ¦¼ÓÔÚ_____________Ö®¼ä£¨Ìî×°ÖÃÐòºÅ£©¡£Æ¿ÖпÉÒÔ·ÅÈë______________________________________¡£

    ¢É±ûͬѧ¿´µ½¼×ͬѧÉè¼ÆµÄ×°ÖúóÌá³öÎÞÐè¶à¼Ó×°Öã¬Ö»Ð轫ԭÀ´ÉÕ±­ÖеÄAgNO3ÈÜÒº»»³ÉÆäËûÈÜÒº¡£ÄãÈÏΪ¿É½«ÈÜÒº»»³É__________________________£¬Èç¹û¹Û²ìµ½_______________________________________µÄÏÖÏó£¬ÔòÖ¤Ã÷ÖÆCl2ʱÓÐHCl»Ó·¢³öÀ´¡£

 

£¨8·Ö£© £¨1£©e,f,d,c £¨2·Ö£©    £¨2£©CuSO4    £¨1·Ö£©

   £¨3£©ÎüÊÕCl2  £¨1·Ö£©   £¨4£©¢Ù¢Û     £¨1·Ö£©  ʪÈóµÄKIµí·ÛÊÔÖ½£¨»òʪÈóµÄÓÐÉ«²¼Ìõ£©£¨1·Ö£©

   £¨5£©×ÏɫʯÈïÊÔÒº£¨1·Ö£©  ÈÜÒº±äºìÇÒ²»ÍÊÉ«£¨1·Ö£©

 

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ΪÁËÖ¤Ã÷ÔÚʵÑéÊÒÖƱ¸µÃµ½µÄCl2Öлá»ìÓÐHCl£¬¼×ͬѧÉè¼ÆÁËÈçÏÂͼËùʾµÄʵÑé×°Ö㬰´ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣮

£¨1£©Çë¸ù¾Ý¼×ͬѧµÄʾÒâͼ£¬ÊµÑé×°ÖôÓ×óÖÁÓÒµÄÁ¬½Ó˳ÐòΪ£º×°Öâڡú
¢Ü
¢Ü
¡ú
¢Û
¢Û
¡ú
¢Ù
¢Ù
£»
£¨2£©×°ÖâÚÖв£Á§ÒÇÆ÷Óоƾ«µÆ¡¢µ¼¹Ü¡¢
Ô²µ×ÉÕÆ¿
Ô²µ×ÉÕÆ¿
¡¢
·ÖҺ©¶·
·ÖҺ©¶·
£»
£¨3£©ÊµÑéÊÒÖƱ¸Cl2µÄ»¯Ñ§·½³ÌʽΪ
MnO2+4HCl£¨Å¨£©
  ¡÷  
.
 
MnCl2+Cl2¡ü+2H2O
MnO2+4HCl£¨Å¨£©
  ¡÷  
.
 
MnCl2+Cl2¡ü+2H2O
£»
£¨4£©×°ÖâÛÖÐCuµÄ×÷ÓÃ
Cl2 +Cu
  ¡÷  
.
 
CuCl2
Cl2 +Cu
  ¡÷  
.
 
CuCl2
£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£»
£¨5£©ÒÒͬѧÈÏΪ¼×ͬѧʵÑéÉè¼ÆÈÔÈ»´æÔÚȱÏÝ£¬²»ÄÜÖ¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ£®Îª´Ë£¬ÒÒͬѧÌá³öÆøÌåͨÈë×°ÖâÙ֮ǰ£¬Òª¼Ó×°Ò»¸ö¼ìÑé×°Öâݣ¬ÒÔÖ¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ£®ÄãÈÏΪװÖâÝÓ¦·ÅÈë
ʪÈóµÄKIµí·ÛÊÔÖ½£¨»òÈóʪµÄÓÐÉ«²¼Ìõ£©
ʪÈóµÄKIµí·ÛÊÔÖ½£¨»òÈóʪµÄÓÐÉ«²¼Ìõ£©
£®Èç¹û×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ£¬×°ÖâÝÓ¦¹Û²ìµ½µÄÏÖÏó
ÊÔÖ½²»±äÀ¶£¨»òÓÐÉ«²¼Ìõ²»ÍÊÉ«£©
ÊÔÖ½²»±äÀ¶£¨»òÓÐÉ«²¼Ìõ²»ÍÊÉ«£©
£®
£¨6£©ÊµÑé½áÊø£¬´¦Àí¶àÓàCl2µÄ³£ÓÃÊÔ¼ÁÊÇ
NaOH
NaOH
£¬Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Cl2+2NaOH¨TNaClO+NaCl+H2O
Cl2+2NaOH¨TNaClO+NaCl+H2O
£®
ΪÁËÖ¤Ã÷ÔÚʵÑéÊÒÖƱ¸Cl2µÄ¹ý³ÌÖлáÓÐË®ÕôÆøºÍHCl»Ó·¢³öÀ´£¬¼×ͬѧÉè¼ÆÁËÈçÏÂͼËùʾµÄʵÑé×°Ö㬰´ÒªÇó»Ø´ðÎÊÌ⣮

£¨1£©Çë¸ù¾Ý¼×ͬѧµÄÒâͼ£¬Á¬½ÓÏàÓ¦µÄ×°Ö㬽ӿÚ˳Ðò£ºb½Ó
e
e
£¬
f
f
½Ó
d
d
£¬
c
c
½Óa£®
£¨2£©UÐιÜÖÐËùÊ¢ÊÔ¼ÁµÄ»¯Ñ§Ê½Îª
CuSO4
CuSO4
£®
£¨3£©×°ÖâÛÖÐCCl4µÄ×÷ÓÃÊÇ
ÎüÊÕÂÈÆø
ÎüÊÕÂÈÆø
£®
£¨4£©ÒÒͬѧÈÏΪ¼×ͬѧʵÑéÖÐÓÐȱÏÝ£¬²»ÄÜÖ¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ£®ÎªÁËÈ·±£ÊµÑé½áÂ۵Ŀɿ¿ÐÔ£¬Ö¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ£¬ÒÒͬѧÌá³öÔÚijÁ½¸ö×°ÖÃÖ®¼äÔÙ¼Ó×°Öâݣ®ÄãÈÏΪװÖâÝÓ¦¼ÓÔÚ
¢Ù¢Û
¢Ù¢Û
Ö®¼ä£¨Ìî×°ÖÃÐòºÅ£©£®Æ¿ÖпÉÒÔ·ÅÈë
ʪÈóµÄµí·ÛKIÊÔÖ½£¨»òʪÈóµÄÓÐÉ«²¼Ìõ£©
ʪÈóµÄµí·ÛKIÊÔÖ½£¨»òʪÈóµÄÓÐÉ«²¼Ìõ£©
£®
£¨5£©±ûͬѧ¿´µ½¼×ͬѧÉè¼ÆµÄ×°ÖúóÌá³öÎÞÐè¶à¼Ó×°Öã¬Ö»Ð轫ԭÀ´ÉÕ±­ÖеÄAgNO3ÈÜÒº»»³ÉÆäËûÈÜÒº£®ÄãÈÏΪ¿É½«ÈÜÒº»»³É
×ÏɫʯÈïÊÔÒº
×ÏɫʯÈïÊÔÒº
£¬Èç¹û¹Û²ìµ½
ÈÜÒº±äºìÇÒ²»ÍÊÉ«
ÈÜÒº±äºìÇÒ²»ÍÊÉ«
µÄÏÖÏó£¬ÔòÖ¤Ã÷ÖÆCl2ʱÓÐHCl»Ó·¢³öÀ´£®

ΪÁËÖ¤Ã÷ÔÚʵÑéÊÒÖƱ¸µÃµ½µÄCl2Öлá»ìÓÐHCl£¬¼×ͬѧÉè¼ÆÁËÈçÏÂͼËùʾµÄʵÑé×°Ö㬰´ÒªÇó»Ø´ðÏÂÁÐÎÊÌâ¡£

(1)Çë¸ù¾Ý¼×ͬѧµÄʾÒâͼ£¬ÊµÑé×°ÖôÓ×óÖÁÓÒµÄÁ¬½Ó˳ÐòΪ£º

×°Öâڡú¡¡¡¡¡¡¡¡ ¡ú¡¡¡¡¡¡¡¡ ¡ú¡¡¡¡¡¡¡¡ £»

(2)×°ÖâÚÖÐÖ÷Òª²£Á§ÒÇÆ÷µÄÃû³Æ___________¡¢___________¡¢___________£»

(3)ʵÑéÊÒÖƱ¸Cl2µÄÀë×Ó·½³ÌʽΪ________________________________£»

(4)×°ÖâÛÖÐCuµÄ×÷Óá¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡(Óû¯Ñ§·½³Ìʽ±íʾ)£»

(5)ÒÒͬѧÈÏΪ¼×ͬѧʵÑéÉè¼ÆÈÔÈ»´æÔÚȱÏÝ£¬²»ÄÜÖ¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ¡£Îª´Ë£¬ÒÒͬѧÌá³öÆøÌåͨÈë×°ÖâÙ֮ǰ£¬Òª¼Ó×°Ò»¸ö¼ìÑé×°Öã¬ÒÔÖ¤Ã÷×îÖÕͨÈëAgNO3ÈÜÒºÖеÄÆøÌåÖ»ÓÐÒ»ÖÖ¡£ÄãÈÏΪװÖÃÓ¦·ÅÈë¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

(6)ʵÑé½áÊø£¬´¦Àí¶àÓàCl2µÄ³£ÓÃÊÔ¼ÁÊÇ______________£¬Óйط´Ó¦µÄÀë×Ó·½³ÌʽΪ______________________________________________¡£

(7)ʵÑéÓõÄAgNO3ÐèÅäÖÆ£¬ÏÂÁÐÇé¿ö»áʹËùÅäÈÜҺŨ¶ÈÆ«¸ßµÄÊÇ(ÌîÐòºÅ) ____¡£

a£®Ä³Í¬Ñ§¹Û²ìÒºÃæµÄÇé¿öÈçͼËùʾ

b£®Ã»½ø¶ÔÉÕ±­¡¢²£Á§°ô½øÐÐÏ´µÓ²Ù×÷

c£®¶¨ÈÝʱ£¬²»É÷³¬¹ýÁ˿̶ÈÏß

d£®AgNO3¹ÌÌå³ÆÁ¿Ê±£¬íÀÂëÉÏÕ´ÓÐÔÓÖÊ

e£®ÈÝÁ¿Æ¿Ê¹ÓÃÇ°ÄÚ±ÚÕ´ÓÐË®Öé

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø