ÌâÄ¿ÄÚÈÝ
º£Ë®Õ¼µØÇò×Ü´¢Ë®Á¿µÄ97.2%¡£Èô°Ñº£Ë®µ»¯ºÍ»¯¹¤Éú²ú½áºÏÆðÀ´£¬¼È¿ÉÒÔ½â¾öµË®×ÊԴȱ·¦µÄÎÊÌ⣬ÓÖ¿ÉÒÔ³ä·ÖÀûÓú£Ñó×ÊÔ´¡£ÊÔÍê³ÉÏÂÁÐÎÊÌ⣺
(1)º£Ë®Öк¬ÓдóÁ¿µÄÂÈ»¯ÄÆ¡£ÂÈ»¯ÄÆÖеĽðÊôÔªËØ»¯ºÏ¼ÛΪ___________¼Û¡£
(2)Ŀǰ¹ú¼ÊÉÏʵÓõġ°º£Ë®µ»¯¡±Ö÷Òª¼¼ÊõÖ®Ò»ÊÇÕôÁ󷨡£ÕôÁó·¨Êǽ«º£Ë®±ä³ÉÕôÆû£¬ÕôÆû¾¹ýÀäÈ´¶øµÃ¸ß´¿¶ÈµË®£¬ÓÉ´Ë¿ÉÅжÏÕôÁó·¨ÊÇ___________£¨Ìî¡°ÎïÀí±ä»¯¡±»ò¡°»¯Ñ§±ä»¯¡±£©¡£
£¨3£©¹¤ÒµÉÏÀûÓõç½â±¥ºÍʳÑÎË®¿ÉÖÆµÃÖØÒª»¯¹¤²úÆ·£¬·´Ó¦Ê½Îª£º
ʳÑÎ+H2O
NaOH+H2+Cl2£¨Î´Å䯽£©¡£¸Ã·´Ó¦ÖÐʳÑεĻ¯Ñ§Ê½ÊÇ_____________________¡£ÀûÓõç½âËùµÃÆøÌåÖÆ36.5%µÄŨÑÎËá100 t£¬×îÉÙÐèÒªÏûºÄʳÑÎ___________t¡£
(4)½üÄêÀ´ÓÐÈËÌá³öÁËÒ»ÖÖÀûÓÃÂȼҵ²úÆ·¼°ÂÈ»¯ÄÆÑ»·ÖÎÀíº¬¶þÑõ»¯Áò·ÏÆø²¢»ØÊÕ¶þÑõ»¯ÁòµÄ·½·¨£¬¸Ã·½·¨Á÷³ÌÈçÏ£º
![]()
д³ö¢Ù¢ÛµÄ»¯Ñ§·´Ó¦·½³Ìʽ£º__________________________£¬__________________________¡£
(1)+1
(2)ÎïÀí±ä»¯
£¨3£©NaCl 58.5
(4)2NaCl+2H2O
H2¡ü+Cl2¡ü+2NaOH H2+Cl2
2HCl
½âÎö:
£¨1£©ÄÆÔÚ»¯ºÏÎïÖÐÏÔ+1¼Û¡££¨2£©ÓÉÓÚÕôÁó·¨Ö»ÊÇË®µÄ״̬ÓÉҺ̬µ½ÆøÌ¬ÔÙµ½ÒºÌ¬µÄ¹ý³Ì£¬ËùÒÔÊôÓÚÎïÀí±ä»¯¡££¨3£©ÓÉÖÊÁ¿Êغ㶨ÂÉ¿ÉÖª£¬Ê³ÑεĻ¯Ñ§Ê½ÎªNaCl£»ÓÉÂÈÔ×ÓÊØºã¿ÉÖª£¬×îÉÙÐèÒªÏûºÄʳÑΣº36.5%¡Á100 t¡Ãx=36.5¡Ã58.5£¬x=58.5 t¡£