ÌâÄ¿ÄÚÈÝ
СËÕ´ò¡¢Î¸Êæƽ¡¢´ïϲ¶¼Êdz£ÓõÄÖкÍθËᣨÖ÷Òª³É·ÖΪÑÎËᣩµÄÒ©Îï¡£
¢ÙÊÐÊÛСËÕ´òƬÿƬº¬0.42 gNaHCO3£¬¸ù¾ÝÒ½Öö£¬Ä³²¡ÈËÒ»´ÎÒª·þÓÃ2ƬСËÕ´òƬ£¬Ôò¿ÉÖкÍÑÎËá mol¡£
¢ÚÈô¸ÄÓÃθÊæƽ£¬Òª´ïµ½Í¬ÑùҩЧ£¬ÐèθÊæƽ Ƭ¡£¡¾Î¸ÊæƽÿƬ0.260gAl£¨OH£©3¡¿
¢Û´ïϲµÄ»¯Ñ§³É·ÖÊÇÂÁºÍþµÄ¼îʽÑΣ¬Æ仯ѧʽΪ£ºAl2Mg6£¨OH£© 16CO3?4H2O¡£Çëд³ö´ïϲºÍθËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ
¢Ù0.01mol ¢Ú1
¢Û Al2Mg6£¨OH£©16CO3?4H2O£«18HCl£½2AlCl3£«6MgCl2£«CO2¡ü£«21H2O
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿