ÌâÄ¿ÄÚÈÝ
äåÒÒÍéÊÇÒ»ÖÖÄÑÈÜÓÚË®¡¢ÃܶÈԼΪˮµÄÃܶȵÄ1.5±¶¡¢·ÐµãΪ38.4¡æµÄÎÞɫҺÌ塣ʵÑéÊÒÖÆÈ¡äåÒÒÍéµÄ·´Ó¦ÈçÏ£º
NaBr+H2SO4(Ũ)
NaHSO4+HBr CH3CH2OH+HBr ¡úCH3CH2Br+H2O
ÒÑÖª·´Ó¦ÎïµÄÓÃÁ¿£º¢ÙNaBr(s) 0.3 mol£¬¢ÚŨÁòËá36 mL£¨98%¡¢ÃܶÈ1.84 g?cm¨C3)£¬
¢ÛÒÒ´¼0.25 mol£¬¢ÜË®25 mL£¬ÆäÖÐÒÒ´¼µÄÃܶÈΪˮµÄÃܶȵÄ4/5¡£![]()
ÊԻشð£º
£¨1£©½öÓÃÈçÏÂͼËùʾÒÇÆ÷°²×°ÖÆÈ¡ºÍÊÕ¼¯äåÒÒÍéµÄ×°Öã¬ÒªÇó´ïµ½°²È«¡¢ËðʧÉÙ¡¢²»ÎÛȾ»·¾³µÄÄ¿µÄ£¬ÓйØÒÇÆ÷£¨Ïà¹Ø½ºÈûÉÏÒÑ´òºÏÊʵĿף¬½º¹Üδ»³ö¡££©µÄÑ¡ÔñºÍÁ¬½Ó˳ÐòΪ £¨ÌîÊý×Ö£©¡£
£¨2£©ÔÚʵÑé¹ý³ÌÖУ¬¿¼Âǵ½Å¨ÁòËáÐÔÖʵÄÌØÊâÐÔ£¬ÊÔ¼Á¼ÓÈëµÄºÏÀí˳ÐòΪ________________£¨ÇëÌîдÊÔ¼ÁµÄ±àºÅ£©£»
£¨3£©ÈôÊÔ¼Á¼ÓÈë¹ý¿ì£¬¿É¿´µ½ÉÕÆ¿ÄÚÓкì×ØÉ«ÆøÌå²úÉú£¬Ð´³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
¡£
£¨4£©Åж¨ÓÐäåÒÒÍéÉú³ÉµÄÏÖÏóÊÇ__________________________¡£´Óר»ÆÉ«µÄ´ÖäåÒÒÍéÖÆÈ¡ÎÞÉ«µÄäåÒÒÍ飬µÚÒ»²½¿ÉÒÔ¼ÓÈëÕôÁóË®»òNaHSO3ÈÜÒº£¬±¾²Ù×÷ÖÐͨ³£Ê¹ÓõÄÒÇÆ÷ÊÇ__________¡£
£¨5£©±¾ÊµÑéµÄ²úÂÊΪ60%£¬Ôò¿ÉÖÆÈ¡äåÒÒÍé g¡£
£¨1£©Á¬½Ó˳ÐòΪ 2¨D9¨D8¨D3¨D4¨D5£¨ÌîÊý×Ö£©¡£
£¨2£©ÊÔ¼Á¼ÓÈëµÄºÏÀí˳ÐòΪ¢Ü¢Ú¢Û¢Ù£¨ÇëÌîдÊÔ¼ÁµÄ±àºÅ£©£»
£¨3£©2NaBr+2H2SO4=?= Na2SO4+2H2O+SO2 ¡ü+ Br2¡ü
£¨4£©¶¡µÄÉÕ±µ×²¿ÓÐÓÍ×´ÒºÌå¾Û¼¯¡£ ·ÖҺ©¶·¡£
£¨5£©16.4
½âÎö
NaBr+H2SO4
NaHSO4+HBr
CH3CH2OH+HBr
CH3CH2Br+H2O
ÒÑÖª·´Ó¦ÎïµÄÓÃÁ¿£¬NaBr(¹ÌÌå)0.3 mol£¬ÒÒ´¼0.25mol£¬Å¨ÁòËá36 mL(98%£¬ÃܶÈ
![]()
ͼ6-2
(1)½öÓÃͼ6-2ËùʾÒÇÆ÷°²×°ÖÆÈ¡ºÍÊÕ¼¯äåÒÒÍéµÄ×°Öã¬ÒªÇó´ïµ½°²È«¡¢ËðʧÉÙ¡¢²»ÎÛȾ»·¾³µÄÄ¿µÄ£¬ÓйØÒÇÆ÷µÄÑ¡ÔñºÍÁ¬½Ó˳ÐòΪ(ÌîÊý×Ö)____________¡£
(2)д³ö²»ÄÜÑ¡ÓõÄÒÇÆ÷(ÌîÒÇÆ÷´úÂ룬Èç¼×¡¢ÒÒ¡¡)¼°ÀíÓÉ¡£
²»ÄÜÑ¡ÓõÄÒÇÆ÷ | ÀíÓÉ |
|
|
|
|
|
|
(3)·´Ó¦Ê±£¬Èôζȹý¸ß£¬¿É¼ûÓÐ×ØÉ«ÆøÌå²úÉú£¬Ð´³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________¡£
(4)´Óר»ÆÉ«µÄ´ÖäåÒÒÍéÖÆÈ¡ÎÞÉ«µÄäåÒÒÍ飬Ӧ¼ÓÈëµÄÊÔ¼ÁÊÇ_________£¬±ØÐëʹÓõÄÒÇÆ÷ÊÇ_________¡£
(5)±¾ÊµÑéµÄ²úÂÊΪ60%£¬Ôò¿ÉÖÆÈ¡äåÒÒÍé_________g¡£
NaBr+H2SO4
NaHSO4+HBr
CH3CH2OH+HBr
CH3CH2Br+H2O
ÒÑÖª·´Ó¦ÎïµÄÓÃÁ¿£ºNaBr(¹ÌÌå)0.3 mol£¬ÒÒ´¼0.25 mol£¬Å¨ÁòËá36 mL(98%£¬ÃܶÈ
(1)½öÓÃÏÂͼËùʾÒÇÆ÷°²×°ÖÆÈ¡ºÍÊÕ¼¯äåÒÒÍéµÄ×°Öã¬ÒªÇó´ïµ½°²È«¡¢ËðʧÉÙ¡¢²»ÎÛȾ»·¾³µÄÄ¿µÄ£¬ÓйØÒÇÆ÷µÄÑ¡ÔñºÍÁ¬½Ó˳ÐòΪ(ÌîÊý×Ö)_______________¡£
![]()
(2)д³ö²»ÄÜÑ¡ÓõÄÒÇÆ÷(ÌîÒÇÆ÷´úÂ룬Èç¼×¡¢ÒÒ¡¡)¼°ÀíÓÉ¡£
²»ÄÜÑ¡ÓõÄÒÇÆ÷ | ÀíÓÉ |
|
|
|
|
|
|
(3)·´Ó¦Ê±£¬Èôζȹý¸ß£¬¿É¼ûÓÐ×ØÉ«ÆøÌå²úÉú£¬Ð´³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________________¡£
(4)´Óר»ÆÉ«µÄ´ÖäåÒÒÍéÖÆÈ¡ÎÞÉ«µÄäåÒÒÍ飬Ӧ¼ÓÈëµÄÊÔ¼ÁÊÇ_________________£¬±ØÐëʹÓõÄÒÇÆ÷ÊÇ_______________________________________¡£
(5)±¾ÊµÑéµÄ²úÂÊΪ60%£¬Ôò¿ÉÖÆÈ¡äåÒÒÍé________________g¡£
äåÒÒÍéÊÇÒ»ÖÖÄÑÈÜÓÚË®µÄÎÞɫҺÌ壬ÃܶÈԼΪˮµÄ1.5±¶£¬·ÐµãΪ38.4 ¡æ¡£ÊµÑéÊÒÖÆÈ¡äåÒÒÍéµÄ·´Ó¦ÈçÏ£º
NaBr+H2SO4
NaHSO4+HBr
CH3CH2OH+HBr
CH3CH2Br+H2O
ÒÑÖª·´Ó¦ÎïµÄÓÃÁ¿£¬NaBr(¹ÌÌå)0.3 mol£¬ÒÒ´¼0.25mol£¬Å¨ÁòËá36 mL(98%£¬ÃܶÈ1.84 g¡¤cm-3)£¬Ë®25 mL£¬ÆäÖÐÒÒ´¼µÄÃܶÈԼΪˮµÄÃܶȵÄ4/5¡£ÊԻشð£º
![]()
ͼ6-2
(1)½öÓÃͼ6-2ËùʾÒÇÆ÷°²×°ÖÆÈ¡ºÍÊÕ¼¯äåÒÒÍéµÄ×°Öã¬ÒªÇó´ïµ½°²È«¡¢ËðʧÉÙ¡¢²»ÎÛȾ»·¾³µÄÄ¿µÄ£¬ÓйØÒÇÆ÷µÄÑ¡ÔñºÍÁ¬½Ó˳ÐòΪ(ÌîÊý×Ö)____________¡£
(2)д³ö²»ÄÜÑ¡ÓõÄÒÇÆ÷(ÌîÒÇÆ÷´úÂ룬Èç¼×¡¢ÒÒ¡¡)¼°ÀíÓÉ¡£
| ²»ÄÜÑ¡ÓõÄÒÇÆ÷ | ÀíÓÉ |
(3)·´Ó¦Ê±£¬Èôζȹý¸ß£¬¿É¼ûÓÐ×ØÉ«ÆøÌå²úÉú£¬Ð´³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________¡£
(4)´Óר»ÆÉ«µÄ´ÖäåÒÒÍéÖÆÈ¡ÎÞÉ«µÄäåÒÒÍ飬Ӧ¼ÓÈëµÄÊÔ¼ÁÊÇ_________£¬±ØÐëʹÓõÄÒÇÆ÷ÊÇ_________¡£
(5)±¾ÊµÑéµÄ²úÂÊΪ60%£¬Ôò¿ÉÖÆÈ¡äåÒÒÍé_________g¡£