ÌâÄ¿ÄÚÈÝ

£¨6·Ö£©ÈçͼËùʾ£¬Ä³ÈÝÆ÷·Ö¸ô³ÉA¡¢BÁ½²¿·Ö£¬AÈÝÆ÷¹Ì¶¨²»±ä£¬BÓпÉÒÆ¶¯µÄ»îÈû£¬ÏÖÔÚAÖгäÈë2molSO2ºÍ1molO2£¬ÔÚBÖгäÈë2 molSO3ºÍ1molN2£¬ÔÚÏàͬÌõ¼þÏ·¢Éú¿ÉÄæ·´Ó¦£º2SO2(g)£«O2(g) 2SO3(g)£¬¸ù¾ÝÏÂÁÐÒªÇóÌî¿Õ£º

 
 

 

 


¢ÅζȲ»±äÏ£¬¹Ì¶¨»îÈûλÖÃÔÚ3´¦²»¶¯£¬´ïµ½Æ½ºâºó£¬ÉèAÈÝÆ÷ѹǿΪPA£¬BÈÝÆ÷ѹǿΪPB£¬ÔòPAÓëPBµÄѹǿÊÇPA      PB (Ìî¡°£¼¡±¡¢¡°£¾¡±¡¢¡°£½¡±£¬ÏÂͬ)£¬AÖÐSO2µÄŨ¶È       BÖÐSO2µÄŨ¶È¡£

¢ÆÈô»îÈûÓÒÒÆµ½5´¦£¬´ïµ½Æ½ºâºó£¬BÖÐSO3Ϊx mol£¬AÖÐSO3Ϊy mol£¬Ôòx     y (Ìî¡°£¼¡±¡¢¡°£¾¡±¡¢¡°£½¡±)¡£

(1) <£¨2·Ö£©   =  £¨2·Ö£©£»(2)< £¨2·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø