ÌâÄ¿ÄÚÈÝ

ijÎÞÉ«ÈÜÒºÖк¬ÓÐK+¡¢Cl-¡¢OH-¡¢SO32-¡¢SO42-£¬Îª¼ìÑéÈÜÒºÖÐËùº¬µÄ¸÷ÖÖÒõÀë×Ó£¬ÏÞÓõÄÊÔ¼ÁÓУºÑÎËá¡¢ÏõËá¡¢ÏõËáÒøÈÜÒº¡¢ÏõËá±µÈÜÒº¡¢äåË®ºÍ·Ó̪ÊÔÒº¡£¼ìÑéÆäÖÐOH-µÄʵÑé·½·¨´ÓÂÔ£¬¼ìÑéÆäËûÒõÀë×ӵĹý³ÌÈçÏÂͼËùʾ¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©°×É«³ÁµíAÓëÊÔ¼Á¢Ú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ__________________________________¡£
£¨2£©ÎÞÉ«ÈÜÒºCÖмÓÈëÊÔ¼Á¢ÛµÄÖ÷ҪĿµÄÊÇ____________________________________¡£
£¨3£©ÊÔÑéÖÐÈôÖ»¼ÓÊÔ¼Á¢Û¶ø²»¼ÓÊÔ¼Á¢Ú£¬¶ÔʵÑéµÄÓ°ÏìÊÇ_______________________¡£
£¨4£©ÆøÌåEͨÈëÊÔ¼Á¢Ü·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ__________________________________¡£

£¨1£© BaSO3 + 2H+  Ba2+ + SO2¡ü + H2O  £¨2·Ö£© 
£¨2£© ÖкÍOH-£¬·ÀÖ¹¶ÔCl-µÄ¼ìÑé²úÉú¸ÉÈÅ£¨2·Ö£©
£¨3£© »áʹSO32-¶ÔSO42-µÄ¼ìÑé²úÉú¸ÉÈÅ£¬²»ÄÜÈ·¶¨SO42-ºÍSO32-ÊÇ·ñ´æÔÚ£¨2·Ö£©
£¨4£© SO2 + Br2 + 2H2O  4H+ + SO42- + 2Br-£¨2·Ö£©

½âÎöÊÔÌâ·ÖÎö£º ÑÇÁòËá¸ùÀë×ÓºÍÁòËá¸ùÀë×Ó¶¼¿ÉÒÔÓë±µÀë×Ó·´Ó¦Éú³É°×É«³Áµí£¬¶øÑÇÁòËá±µ³Áµí²»ÈÜÓÚË®µ«ÄÜÈܽâÔÚËáÖУ¬µ«ÁòËá±µ³Áµí¼È²»ÈܽâÔÚË®ÖУ¬Ò²²»ÈܽâÔÚËáÖС£ÑÇÁòËá¸ùÀë×ÓÔÚÏõËáÈÜÒºÖлᱻÑõ»¯ÎªÁòËá¸ùÀë×Ó£¬Òò´ËÒª¼ìÑéÁòËá¸ùÀë×ӵĴæÔÚʱҪÏÈÅųýµôÑÇÁòËá¸ùÀë×Ó¶ÔÆäµÄ¸ÉÈÅ£¬Òò´Ë¼ÓµÄÊÔ¼Á1ӦΪÑÎËᣬ
¿¼µã£º

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨14·Ö£©

Ã÷·¯[KAl(SO4)2¡¤12H2O] ÔÚÉú²ú¡¢Éú»îÖÐÓй㷺ÓÃ;£ºÒûÓÃË®µÄ¾»»¯£»ÔìÖ½¹¤ÒµÉÏ×÷Ê©½º¼Á£»Ê³Æ·¹¤ÒµµÄ·¢½Í¼ÁµÈ¡£ÀûÓÃÁ¶ÂÁ³§µÄ·ÏÁÏ¡ª¡ªÂÁ»Ò£¨º¬Al ¡¢ Al2O3¼°ÉÙÁ¿SiO2ºÍFeO ¡¤xFe2O3£©¿ÉÖƱ¸Ã÷·¯¡£¹¤ÒÕÁ÷³ÌÈçÏ£º
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ã÷·¯¾»Ë®µÄÔ­ÀíÊÇ£¨ÓÃÀë×Ó·½³Ì±íʾ£©                 
£¨2£©²Ù×÷¢ñÊÇ        £¬²Ù×÷¢òÊÇÕô·¢Å¨Ëõ¡¢         ¡¢¹ýÂË¡¢          ¸ÉÔï¡£
£¨3£©¼ìÑéÂËÒºAÖÐÊÇ·ñ´æÔÚFe2+µÄ·½·¨ÊÇ                     £¨Ö»ÓÃÒ»ÖÖÊÔ¼Á£©
£¨4£©ÔÚÂËÒºAÖмÓÈë¸ßÃÌËá¼ØµÄÄ¿µÄÊÇ            £¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ£¨¸ÃÌõ¼þÏÂFe2+ת»¯ÎªFe3+£¬MnO4- ת»¯ÎªMn2+£©                          ¡£
ÒÑÖª£ºÉú³ÉÇâÑõ»¯Îï³ÁµíµÄpHÈçϱíËùʾ

 
Al(OH)3
Fe(OH)2
Fe(OH)3
¿ªÊ¼³Áµíʱ
3.4
6.3
1.5
ÍêÈ«³Áµíʱ
4.7
8.3
2.8
×¢£º½ðÊôÀë×ÓµÄÆðʼŨ¶ÈΪ0.1 mol¡¤L-1
¸ù¾Ý±íÖÐÊý¾Ý½âÊ͵÷pH=3µÄÄ¿µÄ                                               ¡£
£¨5£©¼ºÖª:ÔÚpH=3¡¢¼ÓÈÈÌõ¼þÏ£¬MnO4- ¿ÉÓëMn2+·´Ó¦Éú³ÉMnO2¡£¼ÓÈëMnSO4·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º                                    ¡£ÂËÔü2º¬ÓеÄÎïÖÊÊÇ                                ¡£
£¨6£©ÒÔAlºÍNiO(OH)Ϊµç¼«£¬KOHÈÜҺΪµç½âÒº¿É×é³ÉÐÂÐÍ¡¢¸ßЧµç³Ø£¬³ä·Åµç¹ý³ÌÖУ¬·¢ÉúNi(OH)2ÓëNiO(OH)Ö®¼äµÄת»¯£¬Ð´³ö·Åµçʱµç³Ø·´Ó¦µÄ»¯Ñ§·½³Ìʽ            ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø