Question

¡¢£¨8·Ö£©µçÈÈ°²È«Ñ¹Á¦¹ø³¹µ×½â¾öÁËѹÁ¦¹øµÄ°²È«ÎÊÌ⣬½â³ýÁËÆÕͨѹÁ¦¹øÀ§ÈÅÏû·ÑÕ߶àÄêµÄ°²È«Òþ»¼£»Ê¡Ê±Ê¡µç(±ÈÆÕͨµç·¹¹ø½ÚÔ¼30%ÒÔÉÏ)¡£ÈçͼÊÇij¿îµçѹÁ¦¹ø¼°ÃúÅÆ£º

¶î¶¨µçѹ	220V	¶î¶¨ÈÝÁ¿	5L
¶î¶¨¹¦ÂÊ	900W	¹¤×÷ѹÁ¦	50~80kPa
¹¤×÷ƵÂÊ	50Hz	ÐͺÅ	M50

£¨1£©ÄãÈÏΪ¸ÃµçѹÁ¦¹øÓ¦¸ÃÑ¡ÓÃÁ½¿×²å×ù»¹ÊÇÈý¿×²å×ù£¬ÎªÊ²Ã´£¿
£¨2£©¸ÃµçѹÁ¦¹øÕý³£¹¤×÷ʱµçÁ÷¶à´ó£¿£¨Ð¡Êýµãºó±£ÁôÁ½Î»Ð¡Êý£©
£¨3£©ÔڸõçѹÁ¦¹øÖÐ×°Èë3kg³õÎÂΪ30¡æµÄË®£¬µ±¼ÓÈȵ½120¡æʱ¸ÕºÃ·ÐÌÚ£¬Ë®ÎüÊÕÁ˶àÉÙÈÈÁ¿£¿
£¨4£©¸Ã°²È«µçѹÁ¦¹øÔÚÕý³£¹¤×÷0.5hÏûºÄµÄµçÄÜÊÇ0.315kWh£¬Í¨¹ý¼ÆËãÅжϸõçѹÁ¦¹øÊǼäЪͨµç¹¤×÷£¬»¹ÊdzÖÐøͨµç¹¤×÷£¿

Answer 1

£¨1£©Èý¿×²å×ù¡¢·Àֹ©µç¡­¡­¡­¡­¡­¡­¡­¡­¡­£¨2·Ö£©
£¨2£©I£½P/U£½900W/220V¡Ö4.09A¡­¡­¡­¡­¡­¡­¡­¡­¡­£¨2·Ö£©
£¨3£©QÎü=cm£¨t-t0£©=4.2¡Á103J/£¨kg¡¤¡æ£©¡Á3kg¡Á90¡æ=1.134¡Á106J¡­¡­£¨2·Ö£©
£¨4£©t=W/P=0.315kWh/0.9kW=0.35h<0.5h¡­¡­¡­¡­¡­¡­¡­¡­¡­£¨1·Ö£©
¼äЪͨµç¹¤×÷¡­¡­¡­¡­¡­¡­¡­¡­¡­£¨1·Ö£©

½âÎö