题目内容
(本题10分)(1)如图1,已知∠AOB,OA=OB,点E在OB边上,四边形AEBF 是平行四边形,请你只用无刻度的直尺在图中画出∠AOB的平分线.(保留作图痕迹,不要求写作法)(2)如图2,在10×10的正方形网格中,点A(0,0)、B(5,0)、C(3,6)、D(-1,3),
①依次连结A、B、C、D四点得到四边形ABCD,四边形ABCD的形状是 ▲ .
②在x轴上找一点P,使得△PCD的周长最短(直接画出图形,不要求写作法);
此时,点P的坐标为 ▲ ,最短周长为 ▲ .
解:(1)如图所示;······································································ 2分
(2)①等腰梯形;·············································································· 4分
②P(,0)·············································································· 6分
(其中画图正确得2分)··················································· 10分
解析:
略
(2)①等腰梯形;·············································································· 4分
②P(,0)·············································································· 6分
(其中画图正确得2分)··················································· 10分
解析:
略
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