题目内容
若
=
=
,则
=
a |
2 |
b |
3 |
c |
4 |
3a-2b+5c |
-6a-b-3c |
-
20 |
27 |
-
.20 |
27 |
分析:设
=
=
=k,求出a=2k,b=3k,c=4k,把a、b、c的值代入,即可求出答案.
a |
2 |
b |
3 |
c |
4 |
解答:解:设
=
=
=k,
则a=2k,b=3k,c=4k,
∴
=
=-
.
故答案为:-
.
a |
2 |
b |
3 |
c |
4 |
则a=2k,b=3k,c=4k,
∴
3a-2b+5c |
-6a-b-3c |
=
3×2k-2×3k+5×4k |
-6×2k-3k-3×4k |
=-
20 |
27 |
故答案为:-
20 |
27 |
点评:本题考查了比例的性质的应用,主要考查学生能否选择适当的方法进行代入,注意:设
=
=
=k,求出a=2k,b=3k,c=4k,再进行代入即可.
a |
2 |
b |
3 |
c |
4 |
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