题目内容
19、化简:
(1)3a-[a-2(-a+b)]+b
(2)6xy-3[3y2-2(x2-2xy-1)].
(1)3a-[a-2(-a+b)]+b
(2)6xy-3[3y2-2(x2-2xy-1)].
分析:(1)先去小括号,后去中括号,然后合并同类项即可;
(2)先去小括号,后去中括号,然后合并同类项即可.
(2)先去小括号,后去中括号,然后合并同类项即可.
解答:解:(1)原式=3a-[a+2a-2b]+b
=3a-a-2a+2b+b
=3b;
(2)原式=6xy-3[3y2-2x2+4xy+2]
=6xy-9y2+6x2-12xy-6
=-9y2+6x2-6xy-6.
=3a-a-2a+2b+b
=3b;
(2)原式=6xy-3[3y2-2x2+4xy+2]
=6xy-9y2+6x2-12xy-6
=-9y2+6x2-6xy-6.
点评:本题考查了整式的加减,解决此类题目的关键是熟记去括号法则,熟练运用合并同类项的法则,这是各地中考的常考点.
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