题目内容
(10分) 如图,Rt△ABC中,∠C = 90°,把Rt△ABC绕着B点逆时针旋转,得到Rt△DBE,点E在AB上.
(1)若∠BDA = 70°,求∠BAC的度数.
(2)若BC = 8,AC = 6,求△ABD中AD边上的高.
(1)∠BAC =
(2)
解析解:(1) 由旋转得△ACB≌△DEB
∴BD = BA
∴∠BAD =∠BDA =
∴∠ABD =
∴∠ABC =∠ABD =
∵∠C =
∴∠BAC =·········································································· 5分
(2) ∵BC = 8,AC = 6,∠C =
∴
∵∠DEB =∠C =且BE = BC = 8,DE ="AC" = 6
∴AE =" AB" – BE = 2
在Rt△DEA中,
设AD边上的高为h
∴
∴······················································· 10分
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