ÌâÄ¿ÄÚÈÝ
40¡¢Ä³´ÖÑÎÑùÆ·Öк¬ÓÐÔÓÖÊÂÈ»¯Ã¾¡¢ÂÈ»¯¸Æ£®Ð¡ÁÖÉè¼ÆÁËÒÔÏÂÌá´¿·½°¸£º

£¨1£©ÈôÊÔ¼ÁaΪÇâÑõ»¯ÄÆ£¬ÊÔ¼ÁbµÄ»¯Ñ§Ê½Îª
£¨2£©Ö¸³ö²Ù×÷AµÄÃû³Æ
£¨3£©²Ù×÷ÖмÓÊÊÁ¿Ï¡ÑÎËáʱ£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
£¨4£©ÓÃÈçͼËùʾװÖýøÐйýÂËʱ£¬Ïò¹ýÂËÆ÷ÄÚÇã×¢ÒºÌåʱ£¬²£Á§°ôÓ¦
A£®²åÈë¹ýÂËÆ÷ÖÐÐÄ£»B£®Ï¶˿¿×¡¹ýÂËÆ÷ÄÚÈÎÒâλÖã»C£®Ï¶˿¿×¡¹ýÂËÆ÷ÄÚÈý²ãÂËÖ½Ò»±ß
£¨5£©ÈôÒ»´Î¹ýÂ˺ó·¢ÏÖÂËÒºÈÔ»ë×Ç£¬ÇÒÂËÖ½Î´ÆÆËð£¬Ðè½Ó׎øÐеIJÙ×÷ʱ
£¨1£©ÈôÊÔ¼ÁaΪÇâÑõ»¯ÄÆ£¬ÊÔ¼ÁbµÄ»¯Ñ§Ê½Îª
Na2CO3
£®£¨2£©Ö¸³ö²Ù×÷AµÄÃû³Æ
Õô·¢
£®£¨3£©²Ù×÷ÖмÓÊÊÁ¿Ï¡ÑÎËáʱ£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
NaOH+HCl¨TNaCl+H2O Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü
£»£¨4£©ÓÃÈçͼËùʾװÖýøÐйýÂËʱ£¬Ïò¹ýÂËÆ÷ÄÚÇã×¢ÒºÌåʱ£¬²£Á§°ôÓ¦
C
£¨ÌîÐòºÅ£©£®A£®²åÈë¹ýÂËÆ÷ÖÐÐÄ£»B£®Ï¶˿¿×¡¹ýÂËÆ÷ÄÚÈÎÒâλÖã»C£®Ï¶˿¿×¡¹ýÂËÆ÷ÄÚÈý²ãÂËÖ½Ò»±ß
£¨5£©ÈôÒ»´Î¹ýÂ˺ó·¢ÏÖÂËÒºÈÔ»ë×Ç£¬ÇÒÂËÖ½Î´ÆÆËð£¬Ðè½Ó׎øÐеIJÙ×÷ʱ
ÔÙ¹ýÂËÒ»´Î
£®·ÖÎö£º£¨1£©ÌâÖдÖÑÎÈÜÒº¼Ó¹ýÁ¿ÊÔ¼ÁÇâÑõ»¯ÄƹýÂË£¬µÃ³ÁµíÇâÑõ»¯Ã¾£»¼Ó¹ýÁ¿ÊÔ¼Á̼ËáÄÆ¹ýÂ˵ã¬ÂËÒººÍ̼Ëá¸Æ¡¢Ì¼Ëáþ£»¹ýÁ¿µÄÇâÑõ»¯ÄÆ¡¢Ì¼ËáÄÆ£¬ÓÃÑÎËá³ýµô£»±ãµÃµ½¾«ÖÂʳÑΣ®
£¨2£©´ÖÑÎÌá´¿ÕýÈ·²½ÖèΪÈܽ⡢¹ýÂË¡¢Õô·¢¡¢¼ÆËã²úÂÊ£®¢Ù´ÖÑÎÖð½¥¼ÓÈëÊ¢ÓÐË®µÄÉÕ±Öб߼ӱßÓò£Á§°ô½Á°è£¬Ö±µ½Èܽ⣻¢Ú¹ýÂËʱעÒâÊÂÏî¡°Ò»Ìù£¬¶þµÍ£¬Èý¿¿¡±£»¢ÛÈôÒ»´Î¹ýÂ˺ó·¢ÏÖÂËÒºÈÔ»ë×Ç£¬ÇÒÂËÖ½Î´ÆÆËð£¬Ðè½Ó׎øÐеIJÙ×÷ʱ£º¶à´Î¹ýÂË£®
£¨2£©´ÖÑÎÌá´¿ÕýÈ·²½ÖèΪÈܽ⡢¹ýÂË¡¢Õô·¢¡¢¼ÆËã²úÂÊ£®¢Ù´ÖÑÎÖð½¥¼ÓÈëÊ¢ÓÐË®µÄÉÕ±Öб߼ӱßÓò£Á§°ô½Á°è£¬Ö±µ½Èܽ⣻¢Ú¹ýÂËʱעÒâÊÂÏî¡°Ò»Ìù£¬¶þµÍ£¬Èý¿¿¡±£»¢ÛÈôÒ»´Î¹ýÂ˺ó·¢ÏÖÂËÒºÈÔ»ë×Ç£¬ÇÒÂËÖ½Î´ÆÆËð£¬Ðè½Ó׎øÐеIJÙ×÷ʱ£º¶à´Î¹ýÂË£®
½â´ð£º½â£º£¨1£©ÓÃ̼Ëá¸ù³ýµô¸Æ¡¢Ã¾Àë×Ó£»£¨2£©´ÖÑÎÌá´¿ÕýÈ·²½ÖèΪ¢ÙÈܽ⣺´ÖÑÎÖð½¥¼ÓÈëÊ¢ÓÐË®µÄÉÕ±Öб߼ӱßÓò£Á§°ô½Á°è£¬Ö±µ½Èܽ⣻¢Ú¹ýÂË£º×¢ÒâÊÂÏî¡°Ò»Ìù£¬¶þµÍ£¬Èý¿¿¡±£»¢ÛÕô·¢£º×¢ÒâÓн϶à¹ÌÌå³öÏÖʱ£¬±ãÍ£Ö¹¼ÓÈÈ£»¢Ü¼ÆËã²úÂÊ£»£¨3£©¹ýÁ¿µÄÇâÑõ»¯ÄÆ¡¢Ì¼ËáÄÆ£¬ÓÃÑÎËá³ý£»£¨4£©¹ýÂËʱעÒâÊÂÏÈý¿¿Ö®Ò»£º²£Á§°ô϶˿¿×¡¹ýÂËÆ÷ÄÚÈý²ãÂËÖ½Ò»±ß£»£¨5£©ÈôÒ»´Î¹ýÂ˺ó·¢ÏÖÂËÒºÈÔ»ë×Ç£¬ÇÒÂËÖ½Î´ÆÆËð£¬Ðè½Ó׎øÐеIJÙ×÷ʱ£º¶à´Î¹ýÂË£®
¹Ê´ðΪ£º£¨1£©Na2CO3£¨2£©Õô·¢ £¨3£©NaOH+HCl¨TNaCl+H2O Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü £¨4£©C £¨5£©ÔÙ¹ýÂËÒ»´Î
¹Ê´ðΪ£º£¨1£©Na2CO3£¨2£©Õô·¢ £¨3£©NaOH+HCl¨TNaCl+H2O Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü £¨4£©C £¨5£©ÔÙ¹ýÂËÒ»´Î
µãÆÀ£º×¢Òâ»ìºÏÎïµÄ·ÖÀë·½·¨£¬Ì½¾¿ÊµÑé²Ù×÷µÄ×¢ÒâÊÂÏî¡°Ò»Ìù£¬¶þµÍ£¬Èý¿¿¡±£¬ÊìÁ·³£ÓÃÒÇÆ÷µÄÃû³ÆºÍÑ¡Óã¬ÕýÈ·ÊéдÓÃÓÚ³ýÔÓÖʵĻ¯Ñ§·½³Ìʽ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿