ÌâÄ¿ÄÚÈÝ

ÖÜÄ©£¬Í¬Ñ§ÃÇÏàÔ¼Ò»ÆðÆï×ÔÐгµÈ¥Å©¼ÒÀÖÔ°´ºÓΣ®ÇëÓÃËùѧµÄ»¯Ñ§ÖªÊ¶»Ø´ðÎÊÌ⣺
£¨1£©Ò»½øÈëÔ°µØ£¬¸Ð¾õÉñÇåÆøˬ£¬Ð¡»ª²»½û¸Ð¿®£ºÕæ²»À¢ÊÇÌìÈ»Ñõ°É°¡£¡Ô­À´Ô°ÖÐÓдóƬÉú³¤Ã¯Ê¢µÄ¸ÌéÙÊ÷£¬ËüÃÇÕýÔÚ½øÐÐ׏âºÏ×÷Ó㬲»¶ÏµØ°Ñ¶þÑõ»¯Ì¼ºÍË®ÔÚÒ¶ÂÌËصÄ×÷ÓÃÏÂÉú³ÉÆÏÌÑÌÇ£¨C6H12O6£©ºÍÑõÆø£¬Æ仯ѧ·½³ÌʽΪ______£®
£¨2£©ÎªÁ˽â¸ÌéÙÊ÷ÊÊÒËÔÚʲôÑùµÄÍÁÈÀ»·¾³ÖÐÉú³¤£¬Ð¡Ã÷²É¼¯ÍÁÑù£¬¼ÓË®Èܽ⣬ÓÃpHÊÔÖ½²âµÃ¸ÃÍÁÈÀ³ÊËáÐÔ£»Ð¡Ã÷ÈÏΪ£¬Èç¹ûÕâƬÍÁµØ½«À´ÒªÖÖֲϲºÃÖÐÐÔÍÁÈÀµÄ×÷ÎӦ¸ÃÓÃ______À´¸ÄÁ¼ÍÁÈÀ£¬¼ÙÉèÍÁÈÀÖеÄËáΪÁòËᣬÇëд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
______£®
£¨3£©ÎªÇø·ÖÌïÀïµÄË®ÊÇӲˮ»¹ÊÇÈíË®£¬¿ÉÓÃ______¼ìÑ飬Éú»îÖпÉÒÔÓÃ______µÄ·½·¨À´½µµÍË®µÄÓ²¶È£®
£¨4£©³´²Ëʱ£¬Ó͹ø×Å»ðÁË£¬³øʦѸËÙÓùø¸Ç¸ÇÃð£¬ÆäÃð»ðÔ­ÀíÊÇ______£®
£¨5£©ÖÐÎç´ó¼ÒÕýÏíÊÜ×ÅÅ©¼ÒÃÀζ£¬Ð¡ºìÀä²»¶¡±»Îó涣ҧÁË£¨ÎóæÄÜ·ÖÃÚ³öÒÏËᣩ£¬ÓÖÍ´ÓÖÑ÷£¬ÏÂÁÐÎïÖÊ¿ÉÓÃÓÚͿĨÒÔ¼õÇáÌÛÍ´µÄÊÇ______£»£¨Ìî×Öĸ£©
A£®Ê³´×£¨pH£¼7£©B£®Ê³ÑÎË®£¨pH=7£©C£®·ÊÔíË®£¨pH£¾7£©

½â£º£¨1£©¹âºÏ×÷ÓõĻ¯Ñ§·½³ÌʽΪ£º6H2O+6CO2C6H12O6+6O2£®
¹ÊÌ6H2O+6CO2C6H12O6+6O2£®
£¨2£©³£ÓÃÊìʯ»Ò¸ÄÁ¼ËáÐÔÍÁÈÀ£¬ÇâÑõ»¯¸ÆºÍÁòËá·´Ó¦ÄÜÉú³ÉÁòËá¸ÆºÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨OH£©2+H2SO4¨TCaSO4+2H2O£®
¹ÊÌÊìʯ»Ò£»Ca£¨OH£©2+H2SO4¨TCaSO4+2H2O£®
£¨3£©ÏòË®ÖмÓÈë·ÊÔíˮʱ£¬Èç¹û²úÉúµÄÅÝÄ­½Ï¶à£¬ÊÇÈíË®£¬Èç¹û²úÉúµÄÅÝÄ­ºÜÉÙ»ò²»²úÉúÅÝÄ­£¬ÊÇӲˮ£®
¹ÊÌ·ÊÔíË®£®
¼ÓÈÈÖó·Ðʱ£¬Ë®ÖеĸÆÀë×ÓÄܹ»ÒÔ̼Ëá¸ÆµÄÐÎʽ´ÓË®ÖÐÎö³ö£¬Ã¾Àë×ÓÄܹ»ÒÔÇâÑõ»¯Ã¾µÄÐÎʽ´ÓË®ÖÐÎö³ö£¬ËùÒÔ¼ÓÈÈÖó·Ð¿ÉÒÔ½µµÍË®µÄÓ²¶È£®
¹ÊÌ¼ÓÈÈÖó·Ð£®
£¨4£©³´²Ëʱ£¬Ó͹ø×Å»ðÁË£¬³øʦѸËÙÓùø¸Ç¸ÇÃð£¬ÆäÃð»ðÔ­ÀíÊǸô¾øÑõÆø£®
¹ÊÌ¸ô¾øÑõÆø£®
£¨5£©ÒÏËáÏÔËáÐÔ£¬¿ÉÒÔÓÃÏÔ¼îÐÔÎïÖÊÖкͣ¬·ÊÔíË®µÄpH´óÓÚ7£¬ÏÔ¼îÐÔ£¬¿ÉÒÔÓ÷ÊÔíˮͿĨÒÔ¼õÇáÌÛÍ´£®
¹ÊÌC£®
·ÖÎö£º£¨1£©¸ù¾Ý·´Ó¦Îï¡¢Éú³ÉÎï¼°ÆäÖÊÁ¿Êغ㶨ÂÉ¿ÉÒÔÊéд»¯Ñ§·½³Ìʽ£»
£¨2£©ÏÔ¼îÐÔµÄÎïÖÊÄܹ»¸ÄÁ¼ËáÐÔÍÁÈÀ£»
£¨3£©¿ÉÒÔÓ÷ÊÔíË®Çø·ÖӲˮºÍÈíË®£¬¼ÓÈÈÖó·Ð¿ÉÒÔ½µµÍË®µÄÓ²¶È£»
£¨4£©Ãð»ðµÄ·½·¨ÓУºÓë¿ÕÆø£¨»òÑõÆø£©¸ô¾ø£»½µÎµ½¿ÉȼÎïµÄ×Å»ðµãÒÔÏ£»³·×ß¿ÉȼÎ
£¨5£©ÏÔËáÐÔµÄÎïÖÊÄܺÍÏÔ¼îÐÔµÄÎïÖÊ·¢Éú·´Ó¦£®
µãÆÀ£º±¾Ì⿼²éµÄÄÚÈݺܶ࣬ÆäÖаüÀ¨»¯Ñ§·½³ÌʽµÄÊéд£¬Êéд»¯Ñ§·½³ÌʽʱҪעÒâËIJ½£¬Ò»ÊÇ·´Ó¦ÎïºÍÉú³ÉÎïµÄ»¯Ñ§Ê½ÒªÕýÈ·£¬¶þÊÇ×ñÑ­ÖÊÁ¿Êغ㶨ÂÉ£¬ÈýÊÇдÉϱØÒªµÄÌõ¼þ£¬ËÄÊÇ¿´ÊÇ·ñÓС°¡ü¡±»ò¡°¡ý¡±£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2013?ͬ°²ÇøÖʼ죩ÖÜÄ©£¬Í¬Ñ§ÃÇÏàÔ¼Ò»ÆðÆï×ÔÐгµÈ¥Å©¼ÒÀÖÔ°´ºÓΣ®ÇëÓÃËùѧµÄ»¯Ñ§ÖªÊ¶»Ø´ðÎÊÌ⣺
£¨1£©Ò»½øÈëÔ°µØ£¬¸Ð¾õÉñÇåÆøˬ£¬Ð¡»ª²»½û¸Ð¿®£ºÕæ²»À¢ÊÇÌìÈ»Ñõ°É°¡£¡Ô­À´Ô°ÖÐÓдóƬÉú³¤Ã¯Ê¢µÄ¸ÌéÙÊ÷£¬ËüÃÇÕýÔÚ½øÐÐ׏âºÏ×÷Ó㬲»¶ÏµØ°Ñ¶þÑõ»¯Ì¼ºÍË®ÔÚÒ¶ÂÌËصÄ×÷ÓÃÏÂÉú³ÉÆÏÌÑÌÇ£¨C6H12O6£©ºÍÑõÆø£¬Æ仯ѧ·½³ÌʽΪ
6H2O+6CO2
 Ì«ÑôÄÜ 
.
Ò¶ÂÌËØ
C6H12O6+6O2
6H2O+6CO2
 Ì«ÑôÄÜ 
.
Ò¶ÂÌËØ
C6H12O6+6O2
£®
£¨2£©ÎªÁ˽â¸ÌéÙÊ÷ÊÊÒËÔÚʲôÑùµÄÍÁÈÀ»·¾³ÖÐÉú³¤£¬Ð¡Ã÷²É¼¯ÍÁÑù£¬¼ÓË®Èܽ⣬ÓÃpHÊÔÖ½²âµÃ¸ÃÍÁÈÀ³ÊËáÐÔ£»Ð¡Ã÷ÈÏΪ£¬Èç¹ûÕâƬÍÁµØ½«À´ÒªÖÖֲϲºÃÖÐÐÔÍÁÈÀµÄ×÷ÎӦ¸ÃÓÃ
Êìʯ»Ò
Êìʯ»Ò
À´¸ÄÁ¼ÍÁÈÀ£¬¼ÙÉèÍÁÈÀÖеÄËáΪÁòËᣬÇëд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
Ca£¨OH£©2+H2SO4¨TCaSO4+2H2O
Ca£¨OH£©2+H2SO4¨TCaSO4+2H2O
£®
£¨3£©ÎªÇø·ÖÌïÀïµÄË®ÊÇӲˮ»¹ÊÇÈíË®£¬¿ÉÓÃ
·ÊÔíË®
·ÊÔíË®
¼ìÑ飬Éú»îÖпÉÒÔÓÃ
¼ÓÈÈÖó·Ð
¼ÓÈÈÖó·Ð
µÄ·½·¨À´½µµÍË®µÄÓ²¶È£®
£¨4£©³´²Ëʱ£¬Ó͹ø×Å»ðÁË£¬³øʦѸËÙÓùø¸Ç¸ÇÃð£¬ÆäÃð»ðÔ­ÀíÊÇ
¸ô¾øÑõÆø
¸ô¾øÑõÆø
£®
£¨5£©ÖÐÎç´ó¼ÒÕýÏíÊÜ×ÅÅ©¼ÒÃÀζ£¬Ð¡ºìÀä²»¶¡±»Îó涣ҧÁË£¨ÎóæÄÜ·ÖÃÚ³öÒÏËᣩ£¬ÓÖÍ´ÓÖÑ÷£¬ÏÂÁÐÎïÖÊ¿ÉÓÃÓÚͿĨÒÔ¼õÇáÌÛÍ´µÄÊÇ
C
C
£»£¨Ìî×Öĸ£©
A£®Ê³´×£¨pH£¼7£©B£®Ê³ÑÎË®£¨pH=7£©C£®·ÊÔíË®£¨pH£¾7£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø